We are going to store 2 bytes of information and then add them together and calculate the result:
| 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 |
| 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 |
| - | - | - | - | - | - | - | - |
| 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 |
| 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 |
| - | - | - | - | - | - | - | - |
| 0 | 1 | 1 | 0 | 0 | 1 | 0 | 1 |
| 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 |
| - | - | - | - | - | - | - | - |
| 0 | 1 | 0 | 1 | 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 0 | 1 | 0 | 1 | 0 |
| - | - | - | - | - | - | - | - |
| 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 |
| 1 | 1 | 0 | 1 | 1 | 0 | 1 | 1 |
| - | - | - | - | - | - | - | - |
| 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 |
| 0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 |
| - | - | - | - | - | - | - | - |
Convert these numbers into binary and store the answer in 1 byte of information:
Add the following pairs of binary numbers from Task 2:
a+b
c+d
e+f